It all depends on how you measure it, and GM is arguably being a bit hyperbolic.
Steven EwingFormer managing editor
Steven Ewing spent his childhood reading car magazines, making his career as an automotive journalist an absolute dream job. After getting his foot in the door at Automobile while he was still a teenager, Ewing found homes on the mastheads at Winding Road magazine, Autoblog and Motor1.com before joining the CNET team in 2018. He has also served on the World Car Awards jury. Ewing grew up ingrained in the car culture of Detroit -- the Motor City -- before eventually moving to Los Angeles. In his free time, Ewing loves to cook, binge trash TV and play the drums.
The just-revealed GMC Hummer EV won't officially launch until fall of 2021, but the new electric truck is already throwing down some impressive numbers -- most notably, 1,000 horsepower and a whopping 11,500 pound-feet of torque. Thing is, that second number isn't necessarily an accurate representation.
It all comes down to what specification you use. GMC's massive number appears to correspond to wheel torque, which is traditional motor torque multiplied through the transmission's drive ratio. Jason Fenske from Engineering Explained has a great video that spells out the difference, a piece he published following Tesla's claim that the Roadster 2.0 will produce more than 7,000 lb-ft of torque. Fenske used a Dodge Challenger SRT Demon as an example. That model produces 972 Newton-meters of engine torque (770 lb-ft). However, multiplied through its gear ratios, you get 14,000 Nm of wheel torque (10,325 lb-ft) in first gear.
Watch this: 2022 GMC Hummer EV trolls Tesla's Cybertruck with 1,000 horsepower
"Most EVs have a final drive reduction ratio of about 8:1 (Tesla Model X is 8.28:1, for example)," Sam Abuelsamid, principal analyst at Navigant Research, told me. "With 11,500 lb-ft and 8:1, that would translate to motor torque of a bit over 1,400 lb-ft, which sounds right with 1,000 hp. [Chevy's] Bolt has a final drive of 7.05:1, while [Tesla's] Model 3 is 9:1, so 8:1 is a reasonable guess until we know more about the Hummer."
When I asked a GMC spokesperson to clarify, I was simply told the final, SAE-specific number would be released closer to the truck's on-sale date, and that the 11,500 lb-ft spec is what the company is sticking with for now. GMC also said the Hummer EV will be able to accelerate to 60 mph in 3 seconds. The truck will be produced at General Motors' Detroit-Hamtramck plant, which is being retooled to only produce electric vehicles.
I recently experienced this torque disparity firsthand. While testing an electric BMW prototype in Germany last summer, an engineer told me the modified 5 Series sedan was producing "around 10,000 Nm on the axles," which equates to 7,357 lb-ft. Then I asked a different engineer for the actual torque coming from the electric motors, and was told "1,150 Nm," a still-not-insubstantial 848 lb-ft.
GMC Hummer EV is a 1,000-hp super truck that moves laterally like a crab
Unfortunately, there's no direct conversion for these two torque figures, so it's hard to say with any certainty how much power the production Hummer EV will offer. My best guess is that it'll still be a pretty big number -- more than 1,000 lb-ft, most likely -- but nothing in five-digit territory.
The problem here isn't that the 11,500 number is incorrect, it's just very misleading (but hey, a big number looks better in a commercial). Of course, there's always the outside possibility the truck will actually have 11,500 lb-ft of torque, but I'm not holding my breath. Either way, I'm pretty stoked to see what's in store for this reborn, electric Hummer.